Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 272: 50

Answer

$V=\sqrt {yg}$

Work Step by Step

Please see the attached image first. Here we use the equation $V=\sqrt {\frac{F}{\mu}}$ where, V - speed of the wave, F - tension force, $\mu$ - mass per unit length $V=\sqrt {\frac{F}{\mu}}$ ; Let's plug known values into this equation. $V=\sqrt {\frac{T}{\mu}}=\sqrt {\frac{mg}{m/y}}=\sqrt {yg}$
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