## Essential University Physics: Volume 1 (4th Edition)

(a) $\omega=19\frac{rad}{s}$ (b) $T=0.33s$ (c) $a_{max}=92\frac{m}{s^2}$
(a) The angular frequency is given as $\omega=\frac{v_{max}}{A}$ We plug in the known values to obtain: $\omega=\frac{4.8}{0.25}$ $\omega=19\frac{rad}{s}$ (b) The time period can be calculated as $T=\frac{2\pi}{T}$ $\implies T=\frac{2(3.1416)}{19.2}$ $T=0.33s$ (c) The maximum acceleration is given as $a_{max}=v_{max}\omega$ $\implies a_{max}=(4.8)(19)$ $a_{max}=92\frac{m}{s^2}$