Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 245: 21

Answer

1.21 seconds

Work Step by Step

We use the equation for the period of a pendulum to find: $T = 2\pi\sqrt{\frac{L}{g}}=2\pi\sqrt{\frac{1.45 \ m}{9.81\ m/s^2}}=2.4156\ s$ The tick occurs every half period, which is $ \frac{2.4156\ s}{2} = \fbox{1.21 seconds}$
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