Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 245: 14

Answer

.158 Hz, 6.32 s

Work Step by Step

The frequency is given by: $ \frac{95}{600s}=.158\ Hz$ The period is 1/f, or: $ T= \frac{600}{95}=6.32\ s$
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