## Essential University Physics: Volume 1 (4th Edition)

The frequency is given by: $$f= \sqrt { \frac{k}{m}} \frac{1} { 2 \pi}$$ This gives: .84 Hz We now find the period: $$T=1/f=1.19 s$$ We now find the maximum velocity: $$1/2mv^2 = 1/2kx^2$$ $$v = \sqrt{ \frac{kx^2}{m}}$$ We plug the given values in to find: 1.32 m/s We know the force is kA, so: $$F=kA=.25*5.6=1.4 N/m$$