Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 245: 16


The answers are below.

Work Step by Step

The frequency is given by: $$ f= \sqrt { \frac{k}{m}} \frac{1} { 2 \pi}$$ This gives: .84 Hz We now find the period: $$T=1/f=1.19 s$$ We now find the maximum velocity: $$ 1/2mv^2 = 1/2kx^2$$ $$ v = \sqrt{ \frac{kx^2}{m}}$$ We plug the given values in to find: 1.32 m/s We know the force is kA, so: $$F=kA=.25*5.6=1.4 N/m$$
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