Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 192: 38

Answer

Axis locates L/6 distance away from the center of the rod.

Work Step by Step

Here we use the parallel - axis theorem, $I= I_{cm}+Md^{2}$ Where, $I$ - the new rotational inertia, d - Distance from the axis through the center of mass to parallel axis & M is the total mass of the object. Let's plug known values into this equation. $\frac{ML^{2}}{9}=\frac{ML^{2}}{12}+Md^{2}$ $L^{2}\frac{(4-3)}{36}=d^{2}$ $\frac{L^{2}}{36}=d^{2}=\gt d=\frac{L}{6}$ Axis locates L/6 distance away from the center of the rod.
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