Answer
$(a)\space 30\space J$
$(b)\space 12\space J$
Work Step by Step
(a) We know that the,
Translational kinetic energy $(K_{T})=\frac{1}{2}m V^{2}$
Let's plug known values into this equation.
$K_{T}=\frac{1}{2}\times2.4\space kg\times (5\space m/s)^{2}=30\space J$
(b) We know that the,
Translational kinetic energy $(K_{R})=\frac{1}{2}I \omega^{2}-(1)$
Let's plug known values into this equation.
Rotational inertia of solid sphere $=\frac{2}{5}MR^{2}$
Where, M - mass of the sphere, R - radius of the sphere.
$(1)=\gt K_{R}=\frac{1}{2}\times\frac{2}{5}MR^{2}(\frac{V^{2}}{R^{2}})=\frac{1}{5}MV^{2}$
$K_{R}= \frac{1}{5}2.4\space kg\times(5\space m/s)^{2}=12\space J$