Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 192: 34

Answer

$(a)\space 30\space J$ $(b)\space 12\space J$

Work Step by Step

(a) We know that the, Translational kinetic energy $(K_{T})=\frac{1}{2}m V^{2}$ Let's plug known values into this equation. $K_{T}=\frac{1}{2}\times2.4\space kg\times (5\space m/s)^{2}=30\space J$ (b) We know that the, Translational kinetic energy $(K_{R})=\frac{1}{2}I \omega^{2}-(1)$ Let's plug known values into this equation. Rotational inertia of solid sphere $=\frac{2}{5}MR^{2}$ Where, M - mass of the sphere, R - radius of the sphere. $(1)=\gt K_{R}=\frac{1}{2}\times\frac{2}{5}MR^{2}(\frac{V^{2}}{R^{2}})=\frac{1}{5}MV^{2}$ $K_{R}= \frac{1}{5}2.4\space kg\times(5\space m/s)^{2}=12\space J$
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