Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 192: 29

Answer

20 minutes

Work Step by Step

We find: $\alpha = \frac{\tau}{I}=\frac{rF}{\frac{1}{2}mr^2}=\frac{.205\times34,000}{.5(7.7\times10^4)(2.4^2)}=.0314\ rads/s^2$ Converting the rotation speed to radians per second, we find: $37.699/.0314=1200\ s =\fbox{20 minutes}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.