Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 192: 29

Answer

20 minutes

Work Step by Step

We find: $\alpha = \frac{\tau}{I}=\frac{rF}{\frac{1}{2}mr^2}=\frac{.205\times34,000}{.5(7.7\times10^4)(2.4^2)}=.0314\ rads/s^2$ Converting the rotation speed to radians per second, we find: $37.699/.0314=1200\ s =\fbox{20 minutes}$
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