Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 12: 26


Please see the work below.

Work Step by Step

We know that $3.0lb=(3.0)(0.454Kg)=1.362Kg$ $2100ft^2=(2100)(9.290\times 10^{-2}m^2)=195.09m^2$ Now $Coverage=\frac{195.09m^2}{1.362Kg}=143\frac{m^2}{Kg}$
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