Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 12: 18

Answer

$(a)\space15.64\space m/s$ $(b)\space51.3\space ft/s$

Work Step by Step

(a) We know 1 mi = 1609 m and 1 h = 3600s First of all, let's convert 35 mi/h into m/h as follows. $35\space mi/h\space = (\frac{35\space mi}{h})\times(\frac{h}{3600\space s})$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=\space 56315\space m/h$ After that let's convert h into s as follows. $35\space mi/h\space =\space 56315\space m/h$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space =\space (\frac{56315\space m}{h})\times(\frac{h}{3600\space s})$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space =\space 15.64\space m/s$ (b) we know 1 m = 3.28 ft Now we can multiply the result in (a) by 3.28 ft/m to get the answer $35\space mi/h\space =\space 15.64\space m/s\space =\space 15.64\space m/s\space \times\space 3.28\space ft/m$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space =\space 51.3\space ft/s$
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