Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 12: 14

Answer

Please see the work below.

Work Step by Step

We know that the mass of the water is $m=14Eg$ $m=14\times 10^{18}$ $m=14\times 10^{18}\frac{1Kg}{1000g}$ $m=14\times 10^{15}Kg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.