Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 1 - Exercises and Problems - Page 12: 23


Please see the work below.

Work Step by Step

We know that $A=350ft^2=(350)(0.3048m)^2=32.516m^2$ $V=1 \space gallon=3.785L$ Now we can find the coverage $coverage=\frac{32.516m^2}{3.785}=8.59\frac{m^2}{L}$
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