Answer
(2E,4Z,6Z,8E)-deca-2,4,6,8-tetraene
Work Step by Step
1. Name the compound by its substituents, parent, unsaturations and functional group:
** First identify the parental chain, and where you should start counting the carbons.
** It doesn't matter if you start from the top or from the bottom.
- Substituent: (none)
- Parent: deca
- Unsaturations: 2,4,6,8-tetraen
- Functional group: e
2. Identify the double bonds and stereocenters.
- 4 double bonds on carbons 2,4,6 and 8.
3. Identify their configurations:
- Double bond carbon 2: Priority groups from right and left are on opposite sides. (2E)
- Double bond carbon 4: Priority groups from right and left are on the same side. (4Z)
- Double bond carbon 6: Priority groups from right and left are on the same side. (6Z)
- Double bond carbon 8: Priority groups from right and left are on opposite sides. (8E)
4. Put all the parts together:
(2E,4Z,6Z,8E)-deca-2,4,6,8-tetraene
