Organic Chemistry As a Second Language, 3e: First Semester Topics

Published by John Wiley & Sons
ISBN 10: 111801040X
ISBN 13: 978-1-11801-040-2

Chapter 7 - Configurations - 7.3 Nomenclature - Problems - Page 148: 7.48

Answer

(2Z,4E)-hepta-2,4-diene

Work Step by Step

1. Name the compound by its substituents, parent, unsaturations and functional group: ** First identify the parental chain, and where you should start counting the carbons. - Substituent: (none) - Parent: hepta - Unsaturations: 2,4-dien - Functional group: e 2. Identify the double bonds and stereocenters. - 2 double bonds, carbons 2 and 4. 3. Identify their configurations: - Double bond on carbon 2: - On the left: Hydrogen (Top), Carbon chain (Bottom). Bottom gets priority. - On the right: Hydrogen(Top), Methyl (Bottom). Bottom gets priority. - Therefore, its configuration is "Z": (2Z) Double bond on carbon 4: - On the left: Hydrogen (Top) and Ethyl (Bottom) Bottom gets priority. - On the right: Carbon chain (Top) and Hydrogen (Bottom) Top gets priority. Therefore, its configuration is "E". (4E) 4. Put all the parts together: (2Z,4E)-hepta-2,4-diene
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