Organic Chemistry As a Second Language, 3e: First Semester Topics

Published by John Wiley & Sons
ISBN 10: 111801040X
ISBN 13: 978-1-11801-040-2

Chapter 7 - Configurations - 7.3 Nomenclature - Problems - Page 148: 7.46

Answer

(3S)-3-methylpent-1-ene

Work Step by Step

1. Name the compound by its substituents, parent, unsaturations and functional group: ** First identify the parental chain, and where you should start counting the carbons. - Substituent: 3-methyl - Parent: pent - Unsaturations: 1-en - Functional group: e 2. Identify the double bonds and stereocenters. - One double bond (carbon 1). - One stereocenter (carbon 3). 3. Identify their configurations: The double bond has on the left: - 1 Hydrogen (Top) - 4 carbons group (Bottom) The bottom groups gets priority. On the right: - 1 Hydrogen (Top) - 1 Hydrogen (Bottom) Theres no priority. - Since there are 3 equal groups, we don't need to name the double bond stereoisomerism. - The stereocenter on carbon 3 is "S". (3S) 4. Put all the parts together: (3S)-3-methylpent-1-ene
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