Answer
The hybridization state for the central carbon in this molecule is $sp$.
Work Step by Step
1. Find the number of bonded atoms.
- There are 2 other carbons : 2 atoms.
2. Find the number of lone pairs.
- A neutral carbon has 4 electrons on the valence shell.
- The central carbon has 4 bonds.
- It doesn't have lone pairs.
3. The hybridization state number will be the sum of these numbers minus 1.
2 + 0 = 2
2 - 1 = 1
- Therefore, the hybridization state is $sp^1 = sp$