The hybridization state for the central carbon in this molecule is $sp$.
Work Step by Step
1. Find the number of bonded atoms. - There are 2 other carbons : 2 atoms. 2. Find the number of lone pairs. - A neutral carbon has 4 electrons on the valence shell. - The central carbon has 4 bonds. - It doesn't have lone pairs. 3. The hybridization state number will be the sum of these numbers minus 1. 2 + 0 = 2 2 - 1 = 1 - Therefore, the hybridization state is $sp^1 = sp$