Answer
The hybridization state for the central carbon in this molecule is $sp^3$.
Work Step by Step
1. Find the number of bonded atoms.
- There is 4 chlorides : 4 atoms.
2. Find the number of lone pairs.
- The central carbon doesn't have lone pairs.
3. The hybridization state number will be the sum of these numbers minus 1.
4 + 0 = 4
4 - 1 = 3
- Therefore, the hybridization state is $sp^3$