Organic Chemistry As a Second Language, 3e: First Semester Topics

Published by John Wiley & Sons
ISBN 10: 111801040X
ISBN 13: 978-1-11801-040-2

Chapter 4 - Geometry - 4.1 Orbitals And Hybridization States - Problems - Page 77: 4.6

Answer

The hybridization state for the central carbon in this molecule is $sp^3$.

Work Step by Step

1. Find the number of bonded atoms. - There is 3 other carbons : 3 atoms. 2. Find the number of lone pairs. - The central carbon have 1 lone pair of electrons. 3. The hybridization state number will be the sum of these numbers minus 1. 3 + 1 = 4 4 - 1 = 3 - Therefore, the hybridization state is $sp^3$
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