The hybridization state for the central carbon in this molecule is $sp^3$.
Work Step by Step
1. Find the number of bonded atoms. - There is 3 other carbons : 3 atoms. 2. Find the number of lone pairs. - The central carbon have 1 lone pair of electrons. 3. The hybridization state number will be the sum of these numbers minus 1. 3 + 1 = 4 4 - 1 = 3 - Therefore, the hybridization state is $sp^3$