Organic Chemistry As a Second Language, 3e: First Semester Topics

Published by John Wiley & Sons
ISBN 10: 111801040X
ISBN 13: 978-1-11801-040-2

Chapter 4 - Geometry - 4.1 Orbitals And Hybridization States - Problems - Page 77: 4.3

Answer

The hybridization state for the central carbon in this molecule is $sp$.

Work Step by Step

1. Find the number of bonded atoms. - There is 2 oxygens : 2 atoms. 2. Find the number of lone pairs. - The central carbon doesn't have lone pairs. 3. The hybridization state number will be the sum of these numbers minus 1. 2 + 0 = 2 2 - 1 = 1 - Therefore, the hybridization state is $sp^1 = sp$
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