Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 84

Answer

6.6 mL of 15 M stock NaOH solution is to be diluted to 500 mL to prepare a 0.2 M solution.

Work Step by Step

According to dilution principle, M1V1 = M2V2 V2 = M1V1/M2 It is given that 500 mL of 0.2 M NaOH solution is to be prepared from 15 M NaOH stock solution. = (500 X 0.2)/15 = 6.6 mL So, 6.6 mL of 15 M stock NaOH solution is to be diluted to 500 mL to prepare a 0.2 M solution.
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