Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 65

Answer

(a) 1.8 moles (b) 0.38 moles (c) 0.2376 moles

Work Step by Step

Molarity = (weight/molecular weight)(1000/V in mL) Molarity = Number of moles / Volume in L Number of moles = Molarity x Volume in L (a) 1.5 L of a 1.2 M NaCl solution Number of moles = 1.2 X 1.5 = 1.8 moles (b) 0.448 L of a 0.85 M NaCl solution Number of moles = 0.448 X 0.85 = 0.38 moles (c) 144 mL of a 1.65 M NaCl solution Number of moles = 1.65 X 0.144 = 0.2376 moles
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