Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 67

Answer

(a) 0.588 L (b) 0.083 L (c) 0.150 L

Work Step by Step

Molarity = Number of moles / Volume in L Volume = Number of moles / Molarity ***It is given that each solution contains 0.15 mol of KCl (a) 0.255 M KCl Volume = 0.15 / 0.255 = 0.588 L (b) 1.8 M KCl Volume = 0.15 / 1.8 = 0.083 L (c) 0.995 M KCl Volume = 0.15 / 0.995 = 0.150 L
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