Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems: 76

Answer

1.67613 L

Work Step by Step

Molarity = (weight/molecular weight)(1000/V in mL) V in mL = (weight/molecular weight)(1000/Molarity) MW of $Mg(NO_{3})_{2}$ = 148.3 V in mL = (87 / 148.3)(1000/0.35) = 1676.13 mL = 1.67613 L
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