Answer
a. 0.568 mole of $CO_2$
b. 0.245 mole of $Al_2O_3$
c. 0.263 mole of $MgCl_2$
Work Step by Step
a.
- Calculate or find the molar mass for $ CO_2 $:
$ CO_2 $ : ( 12.01 $\times$ 1 )+ ( 16.00 $\times$ 2 )= 44.01 g/mol
- Using the molar mass as a conversion factor, find the amount in moles:
$$ 25.0 \space g \times \frac{1 \space mole}{ 44.01 \space g} = 0.568 \space mole$$
b.
- Calculate or find the molar mass for $ Al_2O_3 $:
$ Al_2O_3 $ : ( 26.98 $\times$ 2 )+ ( 16.00 $\times$ 3 )= 101.96 g/mol
- Using the molar mass as a conversion factor, find the amount in moles:
$$ 25.0 \space g \times \frac{1 \space mole}{ 101.96 \space g} = 0.245 \space mole$$
c.
- Calculate or find the molar mass for $ MgCl_2 $:
$ MgCl_2 $ : ( 24.31 $\times$ 1 )+ ( 35.45 $\times$ 2 )= 95.21 g/mol
- Using the molar mass as a conversion factor, find the amount in moles:
$$ 25.0 \space g \times \frac{1 \space mole}{ 95.21 \space g} = 0.263 \space mole$$
