General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 7 - Chemical Reactions and Quantities - Additional Questions and Problems - Page 284: 7.130

Answer

a. 0.235 mole b. 0.0244 mole c. 0.0500 mole

Work Step by Step

a. - Calculate or find the molar mass for $ NH_3 $: $ NH_3 $ : ( 1.008 $\times$ 3 )+ ( 14.01 $\times$ 1 )= 17.03 g/mol - Using the molar mass as a conversion factor, find the amount in moles: $$ 4.00 \space g \times \frac{1 \space mole}{ 17.03 \space g} = 0.235 \space mole$$ b. - Calculate or find the molar mass for $ Ca(NO_3)_2 $: $ Ca(NO_3)_2 $ : ( 40.08 $\times$ 1 )+ ( 14.01 $\times$ 2 )+ ( 16.00 $\times$ 6 )= 164.10 g/mol - Using the molar mass as a conversion factor, find the amount in moles: $$ 4.00 \space g \times \frac{1 \space mole}{ 164.10 \space g} = 0.0244 \space mole$$ c. - Calculate or find the molar mass for $ SO_3 $: $ SO_3 $ : ( 16.00 $\times$ 3 )+ ( 32.07 $\times$ 1 )= 80.07 g/mol - Using the molar mass as a conversion factor, find the amount in moles: $$ 4.00 \space g \times \frac{1 \space mole}{ 80.07 \space g} = 0.0500 \space mole$$
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