General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 7 - Chemical Reactions and Quantities - Additional Questions and Problems - Page 283: 7.127

Answer

a. 5.87 g of $K$ b. 10.6 g of $Cl_2$ c. 15.9 g of $Na_2CO_3$

Work Step by Step

a. - Calculate or find the molar mass for $ K $: $ K $ : 39.10 g/mol - Using the molar mass as a conversion factor, find the mass in g: $$ 0.150 \space mole \times \frac{ 39.10 \space g}{1 \space mole} = 5.87 \space g$$ b. - Calculate or find the molar mass for $ Cl_2 $: $ Cl_2 $ : ( 35.45 $\times$ 2 )= 70.90 g/mol - Using the molar mass as a conversion factor, find the mass in g: $$ 0.150 \space mole \times \frac{ 70.90 \space g}{1 \space mole} = 10.6 \space g$$ c. - Calculate or find the molar mass for $ Na_2CO_3 $: $ Na_2CO_3 $ : ( 22.99 $\times$ 2 )+ ( 12.01 $\times$ 1 )+ ( 16.00 $\times$ 3 )= 105.99 g/mol - Using the molar mass as a conversion factor, find the mass in g: $$ 0.150 \space mole \times \frac{ 105.99 \space g}{1 \space mole} = 15.9 \space g$$
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