Answer
a. 161.44 g/mol
b. 389.9 g/mol
c. 169.11 g/mol
d. 116.16 g/mol
Work Step by Step
a. $ ZnSO_4 $ : ( 65.41 $\times$ 1 )+ ( 16.00 $\times$ 4 )+ ( 32.07 $\times$ 1 )= 161.48 g/mol
b.$ Ca(IO_3)_2 $ : ( 40.08 $\times$ 1 )+ ( 16.00 $\times$ 6 )+ ( 126.9 $\times$ 2 )= 389.9 g/mol
c. $ C_5H_8NNaO_4 $ : ( 22.99 $\times$ 1 )+ ( 1.008 $\times$ 8 )+ ( 12.01 $\times$ 5 )+ ( 14.01 $\times$ 1 )+ ( 16.00 $\times$ 4 )= 169.11 g/mol
d.$ C_6H_{12}O_2 $ : ( 1.008 $\times$ 12 )+ ( 12.01 $\times$ 6 )+ ( 16.00 $\times$ 2 )= 116.16 g/mol