General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 11 - Acids and Bases - 11.2 Bronstead-Lowry Acids and Bases - Questions and Problems - Page 406: 11.15


$NH{_4}^+ + H_2O \rightleftharpoons NH_3 + H_3O^+$

Work Step by Step

1. Identify the reactants. Ammonium ion and water: $NH{_4}^+$ and $H_2O$ 2. Find the products. - As the exercise says, $NH{_4}^+$ will donate an $H^+$ to $H_2O$. Thus, we just need to find the conjugate base for the ammonium ion and the conjugate acid for water. $NH{_4}^+ \longrightarrow NH_3$ $H_2O \longrightarrow H_3O^+$ 3. Write the equation. $NH{_4}^+ + H_2O \rightleftharpoons NH_3 + H_3O^+$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.