Answer
a. Acid: $H_2O$, Base: $CO{_3}^{2-}$
b. Acid: $H_2SO_4$, Base: $H_2O$
c. Acid: $H_3O^+$, Base: $C_2H_3O{_2}^-$
Work Step by Step
a. $H_2O \longrightarrow OH^-$: Donates a proton $(H^+)$: Acid.
$CO_3^{2-} \longrightarrow HCO_3^-$: Receives a proton $(H^+)$: Base.
b. $H_2SO_4 \longrightarrow HSO_4^-$: Donates a proton $(H^+)$: Acid.
$H_2O \longrightarrow H_3O^+$: Receives a proton $(H^+)$: Base.
c. $H_3O^+ \longrightarrow H_2O$: Donates a proton $(H^+)$: Acid.
$C_2H_3O_2^- \longrightarrow HC_2H_3O_2$: Receives a proton $(H^+)$: Base.
