Answer
a. $HCO{_3}^{-}$
b. $H_3O^+$
c. $H_3PO{_4}$
d. $HBr$
e. $HCl{O_4}$
Work Step by Step
- To find the conjugate acid of a base, just add a $H^+$ to its chemical formula.
1. Add a hydrogen:
a. $CO{_3}^{2-} \longrightarrow HCO{_3}^{2-}$
b. $H_2O \longrightarrow H_3O$
c. $H_2PO{_4}^- \longrightarrow H_3PO{_4}^-$
d. $Br^- \longrightarrow HBr^-$
e. $ClO{_4}^- \longrightarrow HCl{O_4}^-$
2. Add 1 to their charges.
a. $HCO{_3}^{2-} \longrightarrow HCO{_3}^{-}$
b. $H_3O \longrightarrow H_3O^+$
c. $H_3PO{_4}^- \longrightarrow H_3PO{_4}$
d. $HBr^- \longrightarrow HBr$
e. $HClO{_4}^- \longrightarrow HCl{O_4}$
