Answer
a. $CO{_3}^{2-}$
b. $CH_3NH_2$
c. $PO{_4}^{3-}$
d. $NO{_2}^-$
e. $BrO^-$
Work Step by Step
- To find the conjugate base of an acid, just remove a $H^+$ from its chemical formula.
1. Remove a hydrogen:
a. $HCO_3^- \longrightarrow CO_3^-$
b. $CH_3NH_3^+ \longrightarrow CH_3NH_2^+$
c. $HPO_4^{2-} \longrightarrow PO_4^{2-}$
d. $HNO_2 \longrightarrow NO_2$
e. $HBrO \longrightarrow BrO$
2. Subtract one from their charges:
a. $CO{_3}^- \longrightarrow CO{_3}^{2-}$
b. $CH_3NH_2^+ \longrightarrow CH_3NH_2$
c. $PO_4^{2-} \longrightarrow PO{_4}^{3-}$
d. $NO_2 \longrightarrow NO{_2}^-$
e. $BrO \longrightarrow BrO^-$
