Answer
$$K_c = 170$$
Work Step by Step
1. Write the equilibrium constant expression:
$$K_c = \frac{[Products]}{[Reactants]} = \frac{[ NH_3 ]^{ 2 }}{[ N_2 ][ H_2 ]^{ 3 }}$$
2. Substitute the values and calculate the constant value:
$$K_c = \frac{( 2.2 )^{ 2 }}{( 0.44 )( 0.40 )^{ 3 }} = 170$$