Answer
The numerical value for $K_c$ for this reaction is 1.5.
Work Step by Step
1. The formula for the equilibrium constant expression is:
$$K_c = \frac{[Products]}{[Reactants]}$$
Also, the coefficients in the equation are the exponents of the concentrations.
$$K_c = \frac{[NO_2]^2}{[N_2O_4]}$$
2. Substitute the concentrations into the expression and evaluate it:
$$K_c = \frac{(0.21)^2}{(0.030)} = 1.5$$