General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 10 - Reaction Rates and Chemical Equilibrium - 10.3 Equilibrium Constants - Questions and Problems - Page 383: 10.15

Answer

Equilibrium constant expression: $$K_c = \frac{[XY]^2}{[X_2][Y_2]}$$ Numerical value: $$K_c = 36$$

Work Step by Step

1. The formula for the equilibrium constant expression is: $$K_c = \frac{[Products]}{[Reactants]}$$ Also, the coefficients in the equation are the exponents of the concentrations. $$K_c = \frac{[XY]^2}{[X_2][Y_2]}$$ 2. Count the amount of each molecule in the diagram: $X_2$: 1 molecule $Y_2$: 1 molecule $XY$: 6 molecules 3. Substitute these numbers into the expression, and evaluate it. $$K_c = \frac{(6)^2}{(1)(1)} = 36$$
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