General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 10 - Reaction Rates and Chemical Equilibrium - 10.3 Equilibrium Constants - Questions and Problems - Page 383: 10.19

Answer

The numerical value of $K_c$ for this reaction is 260

Work Step by Step

1. Write the equilibrium constant expression: $$K_c = \frac{[Products]}{[Reactants]} = \frac{[ CH_4 ][ H_2O ]}{[ CO ][ H_2 ]^{ 3 }}$$ 2. Substitute the values and calculate the constant value: $$K_c = \frac{( 1.8 )( 2.0 )}{( 0.51 )( 0.30 )^{ 3 }} = 260$$
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