General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 35: 1.86

Answer

The volume 1.3 $µm^{3}$ of the particle can be expressed as 1.3 x $10^{-15}$ liters.

Work Step by Step

1 - Convert volume from $µm^{3}$ to $m^{3}$. we know that 1µm = $10^{-6}$ m, therefore 1.3 $µm^{3}$ = 1.3 x $(10^{-6})^{3}$ $m^{3}$ 1.3 $µm^{3}$ = 1.3 x $10^{-18}$ $m^{3}$ 2- Convert the volume from $m^{3}$ to liters. We know that 1 liter = 1 $dm^{3}$, and 1$m^{3}$ =$10^{3}$ $dm^{3}$. 1.3 x $10^{-18}$ $m^{3}$ = 1.3 x $10^{-18}$ x $10^{3}$ $dm^{3}$ 1.3 x $10^{-18}$ $m^{3}$ = 1.3 x $10^{-15}$ $dm^{3}$ 1.3 x $10^{-15}$ $dm^{3}$ = 1.3 x $10^{-15}$ liters So the volume 1.3 $µm^{3}$ of the particle can be expressed as 1.3 x $10^{-15}$ liters
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