Answer
The mass of 5.9 $ cm^{3}$ platinum is 1.3 x $10^{2}$ g .
Work Step by Step
1- We know the density of platinum and the volume of the piece we want to find the mass.
Using the formula for density we can find mass:
d = $\frac{m}{v}$
multiplying both sides with v we will get: d x v =$\frac{m}{v}$ x v
So m = d x v
2- Replace density of platinum 21.4 $\frac{g}{cm^{3}}$ and the volume 5.9 $cm^{3}$ in the formula of mass to find the mass: m = 21.4 $\frac{g}{cm^{3}}$ x 5.9 $cm^{3}$ m = 126 g
(Note: the real number would be 126.26 g , but considering the significant number we wrote 126 g.)
Further considering significant number would bring the mass of platinum to 1.3 x $10^{2}$ g. ( 126 g $\approx$ 130 g = 1.3 x $10^{2}$ g)
