Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 8 - Basic Concepts of Chemical Bonding - Exercises - Page 335: 8.22b

Answer

$Na-Cl$ distance: $2.83$ angstroms $K-F$ distance: $2.71$ angstroms

Work Step by Step

1) Find the ionic radii of the ions: - Ionic radium of $Na^+$: $1.16$ angstroms - Ionic radium of $Cl^-$: $1.67$ angstroms - Ionic radium of $K^+$: $1.52$ angstroms - Ionic radium of $F^-$: $1.19$ angstroms 2) To find $Na-Cl$ distance and $K-F$ distance, we sum the ionic radii of the ions together. In detail, - $Na-Cl$ distance: $1.16+1.67=2.83$ angstroms - $K-F$ distance: $1.52+1.19=2.71$ angstroms
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