Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 8 - Basic Concepts of Chemical Bonding - Exercises - Page 334: 8.14c

Answer

The Lewis symbol for $Sn^{2+}$ is seen in the diagram.
1481360176

Work Step by Step

RULES TO WRITE LEWIS SYMBOL - Find out the number of valence electrons in the atom. - Write the element symbol and around it present each valence electron with one dot to the top, bottom, right or left of that symbol. - Spread out the dots as much as possible (so there would be minimum electron-electron repulsions), and no spots can hold over 2 electrons. 1) $Sn$ is in group 4A, so a neutral $Sn$ atom has 4 electrons in the outermost occupied shell. However, cation $Sn^{2+}$ already loses 2 electrons compared with its neutral $Sn$ atom. So, $Sn^{2+}$ only has 2 electrons in the outermost occupied shell. That means $Sn^{2+}$ has 2 valence electrons. The Lewis symbol of $Sn^{2+}$ would have 2 dots. 2) The dots must spread out as much as possible. So each of the 2 dots would occupy a spot of its own. Eventually, there are 2 spots with 1 electron, and 2 empty spots.
Small 1481360176
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.