Answer
The electron configuration of $Si$ is $$1s^22s^22p^63s^23p^2$$
Work Step by Step
To write the electron configuration of $Si$, we would carry out the following steps:
1) Find out the number of electrons in a $Si$ atom:
The atomic number of $Si$ is 14, so there are 14 electrons in a $Si$ atom.
2) Put the electrons in the shells and subshells in order of increasing level of energy:
- The first 2 electrons would occupy the lowest-level energy subshell $1s$.
- The next 2 electrons occupy the next lowest-level energy subshell $2s$.
- The next 6 electrons occupy the next lowest-level energy subshell $2p$.
- Similarly, the next 2 electrons occupy subshell $3s$.
- Finally, the last 2 electrons occupy subshell $3p$.
Overall, the electron configuration of $Si$, as a result, is: $$ 1s^22s^22p^63s^23p^2$$
