Answer
The element of the configuration is germanium ($Ge$). Its ground-state condensed electron configuration is $$Ge:[Ar]4s^23d^{10}4p^2$$
Work Step by Step
$[Ar]4s^13d^{10}4p^25p^1$
In the excited state, normally there is no loss or addition of electrons. Therefore, to find out which element it is, we still calculate the number of electrons and deduce the atomic number from there.
Looking at the noble gas $[Ar]$, we see there are 18 inner-shell electrons.
Overall, there are $18+1+10+2+1=32$ electrons. So, the atomic number of the element is 32. This element is germanium ($Ge$).
The nearest noble gas of the lower atomic number is $Ar$. Since, $Ge$ has 32 electrons, its ground-state condensed electron configuration is $$Ge:[Ar]4s^23d^{10}4p^2$$
