Answer
The noble gas used in the electron configuration is inconsistent with the outer shell.
Work Step by Step
$[Ne]2s^22p^3$
According to the rule, in the condensed electron configuration, the noble gas used is the one that is $in$ $the$ $previous$ $row$ of the element in the periodic table..
Considering the outer-shell configuration $2s^22p^3$, we see that the outer shell is the second shell, which means the element is in the second row of the periodic table
Thus, the correct noble gas that can be used here is $He$ (the noble gas of the previous row), not $Ne$.
