Answer
The relationship here is that the number of nodes for an $s$ orbital is equal to $n-1$.
Work Step by Step
For an $ns$ orbital,
- The number of peaks is equal with the number of principal quantum number $n$, with the outermost peaks being larger than the innermost ones.
- The number of nodes is equal to $n-1$.
Therefore, the relationship here is that the number of nodes for an $s$ orbital is equal to $n-1$.
