Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises - Page 252: 6.62

Answer

$n=1$, $l=0$, $m_l=0$, orbital $1s$. $n=3$, $l=-3$, $m_l=2$, not allowed. $n=3$, $l=2$, $m_l=-2$, orbital $3d$. $n=2$, $l=0$, $m_l=-1$, not allowed. $n=0$, $l=0$, $m_l=0$, not allowed. $n=4$, $l=2$, $m_l=1$, orbital $4d$. $n=5$, $l=3$, $m_l=0$, orbital $5f$.

Work Step by Step

*NOTES TO REMEMBER: In an orbital designation, - the number represents the value of $n$. - the letter represents the value of $l$, according to the following rule: $l=0$, the letter used is $s$. $l=1$, the letter used is $p$. $l=2$, the letter used is $d$. $l=3$, the letter used is $f$. - The value of $l$ cannot exceed or even be equal with the value of $n$ and cannot be negative. - The value of $n$ must be that $n\gt0$. - The values of $m_l$ only range from $-l$ to $l$, including $0$. $n=1$, $l=0$, $m_l=0$, orbital $1s$. $n=3$, $l=-3$, $m_l=2$, not allowed since $l\lt0$. $n=3$, $l=2$, $m_l=-2$, orbital $3d$. $n=2$, $l=0$, $m_l=-1$, not allowed since for $l=0$, the only possible value of $m_l$ is $0$. $n=0$, $l=0$, $m_l=0$, not allowed since $n\gt0$ is obligatory. $n=4$, $l=2$, $m_l=1$, orbital $4d$. $n=5$, $l=3$, $m_l=0$, orbital $5f$.
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