#### Answer

The amount of reaction that occurs is equal to 0.115 mol.

#### Work Step by Step

1. Divide the amount (in mols) by the coefficient of $N_2O_3$:
$\frac{0.115 mol (N_2O_3)}{ 1 (N_2O_3/reaction)} = 0.115 mol - reaction$

Published by
Cengage Learning

ISBN 10:
1285199049

ISBN 13:
978-1-28519-904-7

The amount of reaction that occurs is equal to 0.115 mol.

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