Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189c: 51b


The amount of reaction that occurs is equal to 0.115 mol.

Work Step by Step

1. Divide the amount (in mols) by the coefficient of $N_2O_3$: $\frac{0.115 mol (N_2O_3)}{ 1 (N_2O_3/reaction)} = 0.115 mol - reaction$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.