Answer
Heat transfer = $ 1.62\times 10^{4}kJ$.
Work Step by Step
1. Divide the amount (in mols) by the coefficient of $CO$:
$\frac{34.8}{ 1} = 34.8 mol - reaction$
2. Find the necessary heat:
$34.8 mol-reaction \times 464.8 kJ/mol-reaction = 1.62\times 10^{4}kJ$
