## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189c: 50a

#### Answer

Heat transfer = $1.62\times 10^{4}kJ$.

#### Work Step by Step

1. Divide the amount (in mols) by the coefficient of $CO$: $\frac{34.8}{ 1} = 34.8 mol - reaction$ 2. Find the necessary heat: $34.8 mol-reaction \times 464.8 kJ/mol-reaction = 1.62\times 10^{4}kJ$

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