Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189c: 51c


The amount of reaction that occurs is equal to 0.0790 mol.

Work Step by Step

Molar Mass ($NO$): 14.01* 1 + 16* 1 = 30.01g/mol 1. Calculate the amount in moles: $4.73g \times \frac{1 mol (NO)}{ 30.01} = 0.158 mol$ 2. Divide the amount by the coefficient of $NO$: $\frac{0.158}{ 2} = 0.0790 mol - reaction$
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