## Chemistry: The Molecular Science (5th Edition)

Heat transfer = $66.9kJ$
1. Divide the amount (in moles) by the coefficient of $C$: $\frac{0.432}{ 3} = 0.144 mol - reaction$ 2. Find the necessary heat: $0.144mol-reaction \times 464.8 kJ/mol-reaction = 66.9kJ$