Answer
$Co$ is not the identity of the metal, because that would not give 0.376 g of carbon dioxide.
Work Step by Step
1. Calculate the number of moles of $CoCO_3$:
58.93* 1 + 12.01* 1 + 16* 3 = 118.94g/mol
$1.056g \times \frac{1 mol}{ 118.94g} = 8.878 \times 10^{-3}mol (CoCO_3)$
- The balanced reaction is:
$CoCO_3 -- \gt CoO + CO_2$
The ratio of $CoCO_3$ to $CO_2$ is 1 to 1:
$8.878 \times 10^{-3} mol (CoCO_3) \times \frac{ 1 mol(CO_2)}{ 1 mol (CoCO_3)} = 8.878 \times 10^{-3}mol (CO_2)$
2. Calculate the mass of $CO_2$:
12.01* 1 + 16* 2 = 44.01g/mol
$8.878 \times 10^{-3} mol \times \frac{ 44.01 g}{ 1 mol} = 0.391g (CO_2)$
