Answer
$CaF_2(s) + H_2SO_4(aq) -- \gt 2HF(g) + CaSO_4(s)$
$CaF_2$: Calcium fluoride;
$H_2SO_4$: Dihydrogen sulfate or Sulfuric acid;
$HF$: Hydrogen fluoride or Hydrofluoric acid;
$CaSO_4$: Calcium sulfate.
Work Step by Step
1. Balance the reaction:
- This is a double displacement reaction.
- Analyzing the initial number of each ion in each side:
$CaF_2(s) + H_2SO_4(aq) -- \gt HF(g) + CaSO_4(s)$
$Ca^{2+}$ : 1 and 1 - Balanced.
$F^-$ : 2 and 1 - Not balanced.
$H^+$: 2 and 1 - Not balanced.
$SO_4^{2-}$: 1 and 1 - Balanced.
Therefore, we just need to add a hydrogen and a fluoride to the products side, and we can do that by adding one more $HF$:
$CaF_2(s) + H_2SO_4(aq) -- \gt 2HF(g) + CaSO_4(s)$
Since that did not effect anything else, the reaction is balanced.
2. Name the compounds:
Since all the compounds are ionic:
- Identify the cation; its name will be the first name of the compound.
- Identify the anion; its name will be the second name of the compound.
For $H_2SO_4$, the hydrogen will receive a "di", because this compound has 2 $H^+$.
