Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 3 - Chemical Reactions - Questions for Review and Thought - General Questions - Page 148g: 108a


$CaF_2(s) + H_2SO_4(aq) -- \gt 2HF(g) + CaSO_4(s)$ $CaF_2$: Calcium fluoride; $H_2SO_4$: Dihydrogen sulfate or Sulfuric acid; $HF$: Hydrogen fluoride or Hydrofluoric acid; $CaSO_4$: Calcium sulfate.

Work Step by Step

1. Balance the reaction: - This is a double displacement reaction. - Analyzing the initial number of each ion in each side: $CaF_2(s) + H_2SO_4(aq) -- \gt HF(g) + CaSO_4(s)$ $Ca^{2+}$ : 1 and 1 - Balanced. $F^-$ : 2 and 1 - Not balanced. $H^+$: 2 and 1 - Not balanced. $SO_4^{2-}$: 1 and 1 - Balanced. Therefore, we just need to add a hydrogen and a fluoride to the products side, and we can do that by adding one more $HF$: $CaF_2(s) + H_2SO_4(aq) -- \gt 2HF(g) + CaSO_4(s)$ Since that did not effect anything else, the reaction is balanced. 2. Name the compounds: Since all the compounds are ionic: - Identify the cation; its name will be the first name of the compound. - Identify the anion; its name will be the second name of the compound. For $H_2SO_4$, the hydrogen will receive a "di", because this compound has 2 $H^+$.
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